具体看代码
dp转移方程
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#include <iostream>
using namespace std;
const int maxn = 1000 +5;
int n;
int a[maxn][maxn];
int f[maxn][maxn];
int ans;
void init() {
cin >> n;
for(int i =1;i<=n ;i++){
for(int j =1;j<=i;j++)
cin >> a[i][j];
}
for(int i =0;i<=1000;i++)
for (int j = 0; j <= 1000; j++)
f[i][j] = -1;
}
// dfs(i,j) 表示从i,j这个点开始向下走,到
// 最后一层的最值
int dfs(int i,int j)
{
if( i == n+1) {
return 0;
}
if( f[i][j] != -1)
return f[i][j];
int x = dfs(i+1,j);
int y = dfs(i+1,j+1);
if( x > y)
f[i][j] = x;
else
f[i][j] = y;
f[i][j] += a[i][j];
return f[i][j];
}
int main(int argc, char const *argv[])
{
init();
dfs(1,1);
cout << f[1][1] << endl;
return 0;
}